Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
For example,
If n = 4 and k = 2, a solution is:
If n = 4 and k = 2, a solution is:
[ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ]
Analysis:
Standard DFS problem. Details see the code.
Source Code:
class Solution {
public:
vector<vector<int> > res;
void dfs(vector<int> &cand, int st, int ed, vector<int> &lr){
if (lr.size()==ed){
res.push_back(lr);
return;
}
for (int i = st; i< cand.size();i++){
lr.push_back(cand[i]);
dfs(cand,i+1,ed,lr);
lr.pop_back();
}
}
vector<vector<int> > combine(int n, int k) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
res.clear();
if ((k<1)||(n<1)||(k>n)){return res;}
vector <int> cand;
for (int i = 1; i<=n;i++){
cand.push_back(i);
}
vector<int> lr;
dfs(cand,0,k,lr);
return res;
}
};
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