Given two integers n and k, return all possible combinations of k numbers out of 1 ... n.
For example,
If n = 4 and k = 2, a solution is:
If n = 4 and k = 2, a solution is:
[ [2,4], [3,4], [2,3], [1,2], [1,3], [1,4], ]
Analysis:
Standard DFS problem. Details see the code.
Source Code:
class Solution { public: vector<vector<int> > res; void dfs(vector<int> &cand, int st, int ed, vector<int> &lr){ if (lr.size()==ed){ res.push_back(lr); return; } for (int i = st; i< cand.size();i++){ lr.push_back(cand[i]); dfs(cand,i+1,ed,lr); lr.pop_back(); } } vector<vector<int> > combine(int n, int k) { // Start typing your C/C++ solution below // DO NOT write int main() function res.clear(); if ((k<1)||(n<1)||(k>n)){return res;} vector <int> cand; for (int i = 1; i<=n;i++){ cand.push_back(i); } vector<int> lr; dfs(cand,0,k,lr); return res; } };
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