Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
Analysis:
This is a DP problem.
Init: A[0][i] = A[0][i-1]+grid[0][i];
A[i][0] = A[i-1][0]+grid[i][0];
State Change func:
A[i][j] = min(A[i-1][j]+grid[i][j], A[i][j-1]+grid[i][j]);
Source Code:
class Solution {
public:
int minPathSum(vector<vector<int> > &grid) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
if (grid.empty()){return 0;}
int m=grid.size();
int n=(*grid.begin()).size();
vector<vector<int> > a(m,vector<int>(n,0));
a[0][0]=grid[0][0];
for (int i=1;i<n;i++){ a[0][i]=a[0][i-1]+grid[0][i];}
for (int i=1;i<m;i++){ a[i][0]=a[i-1][0]+grid[i][0];}
for(int i=1;i<m;i++){
for (int j=1;j<n;j++){
a[i][j]= min( a[i][j-1]+grid[i][j], a[i-1][j]+grid[i][j]);
}
}
return a[m-1][n-1];
}
};
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