Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given
Given
Analysis:Given
1->1->2, return 1->2.Given
1->1->2->3->3, return 1->2->3.This problem is a classic one using the pointers.
Idea is just link the duplicates to the next element.
e.g. 1->1->1->2->3->4
1st step 1 ----->1->2->3->4
2nd step 1 --------->2->3->4
Code:
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *deleteDuplicates(ListNode *head) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
if (head==NULL){return NULL;}
if (head->next==NULL){return head;}
ListNode* list = head;
while (head->next!=NULL){
if (head->next->val==head->val){
head->next=head->next->next;
}else{
head = head->next;
}
}
return list;
}
};
will the solution have memory leak at
ReplyDeleteif (head->next->val==head->val){
head->next=head->next->next;
}?
Should this be:
if (head->next->val==head->val){
ListNode *temp = head->next;
head->next=head->next->next;
delete temp;
}?
Thanks.